RDD变换和操作只能由驱动调用
问题说明
错误：
org.apache.spark.SparkException： RDD的转换和操作只能由司机被调用，而不是内的其他变换;例如，rdd1.map（X => rdd2.values.count（）* X）是无效的，因为价值观改造和计数不能在rdd1.map改造内部执行的操作。欲了解更多信息，请参阅SPARK-5063。
org.apache.spark.SparkException: RDD transformations and actions can only be invoked by the driver, not inside of other transformations; for example, rdd1.map(x => rdd2.values.count() * x) is invalid because the values transformation and count action cannot be performed inside of the rdd1.map transformation. For more information, see SPARK-5063.
def computeRatio(model: MatrixFactorizationModel, test_data: org.apache.spark.rdd.RDD[Rating]): Double = {
val numDistinctUsers = test_data.map(x => x.user).distinct().count()
val userRecs: RDD[(Int, Set[Int], Set[Int])] = test_data.groupBy(testUser => testUser.user).map(u => {
(u._1, u._2.map(p => p.product).toSet, model.recommendProducts(u._1, 20).map(prec => prec.product).toSet)
})
val hitsAndMiss: RDD[(Int, Double)] = userRecs.map(x => (x._1, x._2.intersect(x._3).size.toDouble))
val hits = hitsAndMiss.map(x => x._2).sum() / numDistinctUsers
return hits
}
我使用 MatrixFactorizationModel.scala 的方法，我一定要在映射用户，然后调用方法来获取每个用户的结果。通过这样做，我介绍嵌套映射，我相信会引起问题：
I am using the method in MatrixFactorizationModel.scala, I have to map over users and then call the method to get the results for each user. By doing that I introduce nested mapping which I believe cause the issue:
我知道这个问题实际采取在地方：
I know that issue actually take place at:
val userRecs: RDD[(Int, Set[Int], Set[Int])] = test_data.groupBy(testUser => testUser.user).map(u => {
(u._1, u._2.map(p => p.product).toSet, model.recommendProducts(u._1, 20).map(prec => prec.product).toSet)
})
由于同时映射在我打电话 model.recommendProducts
Because while mapping over I am calling model.recommendProducts
正确答案
MatrixFactorizationModel 是一个分布式的模式，所以你不能简单地从一个动作或转换调用它。最接近你做什么，这里是这样的：
MatrixFactorizationModel is a distributed model so you cannot simply call it from an action or a transformation. The closest thing to what you do here is something like this:
import org.apache.spark.rdd.RDD
import org.apache.spark.mllib.recommendation.{MatrixFactorizationModel, Rating}
def computeRatio(model: MatrixFactorizationModel, testUsers: RDD[Rating]) = {
val testData = testUsers.map(r => (r.user, r.product)).groupByKey
val n = testData.count
val recommendations = model
.recommendProductsForUsers(20)
.mapValues(_.map(r => r.product))
val hits = testData
.join(recommendations)
.values
.map{case (xs, ys) => xs.toSet.intersect(ys.toSet).size}
.sum
hits / n
}
注：
不同的是一个昂贵的操作，完全obsoletely在这里，因为你可以得到从分组数据
相同的信息
- 而不是
GROUPBY其次是投影（地图），项目第一和组以后。没有理由，如果你想只是一个产品ID传送充分的收视率。
distinctis an expensive operation and completely obsoletely here since you can obtain the same information from a grouped data- instead of
groupByfollowed by projection (map), project first and group later. There is no reason to transfer full ratings if you want only a product ids.
这篇好文章是转载于：编程之路
