TypeError:第参数必须是 pandas 对象的可迭代对象，您传递了类型为"DataFrame"的对象，
it1352
帮助1人
问题说明
我有一个大数据框，我尝试将其拆分，并在concat之后. 我用
I have a big dataframe and I try to split that and after concat that. I use
df2 = pd.read_csv('et_users.csv', header=None, names=names2, chunksize=100000)
for chunk in df2:
chunk['ID'] = chunk.ID.map(rep.set_index('member_id')['panel_mm_id'])
df2 = pd.concat(chunk, ignore_index=True)
但是它返回一个错误
TypeError: first argument must be an iterable of pandas objects, you passed an object of type "DataFrame"
我该如何解决?
正确答案
#1
IIUC，您需要以下内容:
IIUC you want the following:
df2 = pd.read_csv('et_users.csv', header=None, names=names2, chunksize=100000)
chunks=[]
for chunk in df2:
chunk['ID'] = chunk.ID.map(rep.set_index('member_id')['panel_mm_id'])
chunks.append(chunk)
df2 = pd.concat(chunks, ignore_index=True)
您需要将每个块添加到列表中，然后使用concat将它们全部连接起来，我也认为ignore_index可能不是必需的，但我可能是错的
You need to append each chunk to a list and then use concat to concatenate them all, also I think the ignore_index may not be necessary but I may be wrong
这篇好文章是转载于：编程之路
